1.

A ballon with mass 'm’ is descending down with an acceleration ‘a' (where a le g). How much mass should be removed from it so that is starts moving up with an acceleration ‘a ’ ?

Answer»

`(2ma)/(G+a)`
`(2ma)/(g-a)`
`(ma)/(g+a)`
`(ma)/(g-a)`

SOLUTION :
from FIGURE (2)
F- (m-m) g= (m-m) a wherem= m - m
mg - ma - mg + mg = ma = m a
mg+ma = ma
m(g + a ) = 2 ma
`m= (2ma )/( g+ a)`


Discussion

No Comment Found