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A balloon filled with hydrogen has a volume of 1000 litres and its mass is 1 kg. what would be the volume of the block of very light material which it can just lift? One litre of material has mass of 91.3 gram. (Density of air = 1.3 gram//litre). |
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Answer» SOLUTION :Let V and M be the volume and MASS of the balloon respectively. Let `upsilon_(1) , m_(1)` and `rho_(1)` be the volume , mass and density of the block to be filled. Here, `V = 1000` litres`= 1000 xx 10^(-3)m^(3) = 1m^(3)`, `rho_(1) = 91.3 G//litre = 91.3 kg m^(-3)`, `rho_(a) = 1.3 g//litre = 1.3 kg m^(-3)`, TOTAL volume of the balloon and block = `V + upsilon_(1)`. The volume of air displaced = `(V +upsilon_(1))`. If `rho_(a)` is teh density of air, then weight of air displaced The balloon can lift the block if Weight of balloon and block = weight of air displaced i.e., `(M+m_(1))g = (V + upsilon_(1)) rho_(a)g` `or (M+upsilon_(1)rho_(1))g = (V+upsilon_(1))rho_(a)g` This gives, `upsilon_(1) = (Vrho_(a)-M)/(rho_(1)-rho_(a)) = (1xx1.3-1)/(91.3 = 1.3) = 0.3/90 m^(3)` `=(0.3 xx 1000)/(90) litre = 3.33litres`. |
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