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A balloon starts from rest from the ground and moves with uniform acceleration g/8. When it reaches a height h a ball is dropped from it. Find the time taken by the ball to reach the ground.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Velocity of ballon when is at a height is <br/> `v=sqrt((2gh)/(8)=sqrt(gh)/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/> `-h=vt-1/2gt^(2)` <br/> `-h=sqrt(gh)/2 t-1/2gt^2` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_SLV_059_S01.png" width="80%"/> <br/> `-h=sqrt(gh)/2 t-1/2 gt^(2)` <br/> `1/2 gt^(2)-sqrt(gh)/2 t-h=0` <br/> <a href="https://interviewquestions.tuteehub.com/tag/simplifying-7714583" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLIFYING">SIMPLIFYING</a> and taking only the <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> value as <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> value of t is not acceptable we get `t=2 sqrt(h/g)`</body></html>


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