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A "bar" magnet is at right angles to a uniform magnetic field. The couple acting on the magnet is to be one fourth by rotating it from the position. The angle of rotation isA. `Sin^(-1)(0.25)`B. `90^(@)-Sin^(-1)(0.25)`C. `Cos^(-1)(0.25)`D. `90^(@)-Cos^(-1)(0.25)` |
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Answer» Correct Answer - B `C=MB sin theta` |
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