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A bar magnet is placed with its North pole pointing North. Neutral point is at `12 cm`. Another magnet is now placed on the first magnet, then the neutral point is found to be at `8 cm`. The ratio of their magnetic moments isA. `3:2`B. `27:19`C. `9:4`D. `9:5` |
Answer» Correct Answer - B `(mu_(0))/(4pi)(M_(1))/(12^(3))=B_(H)` and `(mu_(0))/(4pi)((M_(1)-M_(2)))/(8^(3))=B_(H)` |
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