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A bar magnet made of steel has a magnetic moment of `2.5 A m^2` and mass of `6.6 xx 10^(-5) kg`. If the density of steel is `7.9 xx 10^3 kg m^(-3)`, find the intensity of magnetization of the magnet.A. `1.0 xx 10^(6) Am`B. `4.0 xx 10^(6) Am`C. `3.0 xx10^(6) Am`D. `8.0 xx 10^(6)Am` |
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Answer» Correct Answer - B `x=2.1xx10^(-5)` Increase in magnetic held =`B-B_(0)` `=B_(0)+B_(1)-B_(0)` `B_(1)` Now % increase in magnetic field =`(B_(1))/(B_(0))xx100` `=(mu_(0)I)/(mu_(0)H)xx100` `(I)/(H)xx100` `x xx 100` `2.1xx10^(-5)xx100` `=2.1xx10^(-3)` |
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