InterviewSolution
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InterviewSolution
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A bar magnet of length `10cm` has a pole strength of `20Am`. Find the magnetic field strength at a distance of `10cm` from its centre on (i) its axial line and on (ii) its equatorial line. |
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Answer» Correct Answer - (i) `7*1xx10^-3T` (ii) `1*43xx10^-4T` Here, `2l=10cm=0*1m, m=20Am` `d=10cm=0*1m` (i) On axial line `B_1=(mu_0)/(4pi)(2M)/((d^2-l^2)^2)=(mu_0)/(4pi)(2xx(mxx2l))/((d^2-l^2)^2)` `=(10^-7xx2xx20xx0*1)/([(0*1)^2-((0*1)/(2))^2]^2)=(4xx10^-7)/((0*0075)^2)` `=7*5xx10^-3T` (ii) On equatorial line `B_2=(mu_0)/(4pi)(M)/((d^2+l^2)^(3//2))=(10^-7xx20xx0*1)/((0*1^2+0*05^2)^(3//2))` `=1*43xx10^-4T` |
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