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A "bar" magnet of length `16 cm` has a pole strength of `500` milli amp.`m`. The angle at which it should be placed to the direction of external magnetic field of induction `2.5` gauses so that it may experience a torque of `sqrt(3)xx10^(-5)Nm` isA. `pi`B. `pi//2`C. `pi//3`D. `pi//6` |
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Answer» Correct Answer - C `C=MB sin theta` |
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