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A bar magnet of magnetic moment `10Am^(2)` has a cross sectional area of `2.5xx10^(-4)m^(2)` . If the intensity of magnetisation of the magnet is `10^(6)A//m`, then the length of magnet isA. 0.4 mB. 0.04 cmC. 0.04mD. 50cm |
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Answer» Correct Answer - C `M=10 Am^(2),A=2.5xx10^(-4)M^(2),` `I=10^(6) A//m, l=?` `I =(M)/(V)=(M)/(A.l)` `therefore l=(M)/(AI)=(10)/(2.5xx10^(-4)xx10^(6))` |
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