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A bar magnet of magnetic moment `M_(1)` is axially cut into two equal parts. If these two pieces are arranged perpendiucular to each other, the resultant magnetic moment is `M_(2)`. Then the vale of `(M_(1))/(M_(2))` isA. `1:sqrt(2)`B. `1:1`C. `sqrt(2):1`D. `1:2` |
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Answer» Correct Answer - C `M_(2)=sqrt(((M_(1))/(2))^(2)+((M_(1))/(2))^(2))=sqrt(2)(M_(1))/(2)` `therefore M_(1)/M_(2)=(2)/sqrt(2)=sqrt(2)/(1)` |
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