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A bar of mass `M` and length `L` is in pure traslatory motion with its of mass velocity `V` . It collides with and sticks to a second identical bar which is initially at rest . `(` Assume that it bocomes one composite bar of length `2L)`. The angular velocity of the composite bar will be A. `(3)/(4)(V)/(L)` clockwiseB. `(4)/(3)(VL)/(L)` clockwiseC. `(3)/(4)(V)/(L)` counterclockwiseD. `(V)/(L)` counterclockwise |
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Answer» Correct Answer - C Cons. Of ang. Momentum about `P` gives `MV(L)/(2)=((2M)(2L)^(2))/(12)omega` `(V)/(2)=(2Lomega)/(3)` `omega=(3V)/(4L), ` counterclockwise `Ans . (C )` |
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