1.

A bar of mass m resting on a smooth horizontal plane starts moving due to the force F=mg/3 of constant magnitude. In the process of its rectilinear motion the angle alpha between the direction of this force and the horizontal varies as alpha=as, where a is a constant and s is the distance traversed by the bar from its initial position. Find the velocity of the bar as a function of the angle 'alpha'

Answer»

SOLUTION :`V=sqrt(2G SIN ALPHA)/(3A)`


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