A base ball of mass 200g is moving with a velocity of 30 xx 10^(2) m s^(-1). If we can locate the base ball with an error equal to the wavelength of the light used (5000 Å), how will the uncertainty in momentum be compared with the total momentum of the base ball ?

A base ball of mass 200g is moving with a velocity of 30 xx 10^(2) m s

1.	A base ball of mass 200g is moving with a velocity of 30 xx 10^(2) m s^(-1). If we can locate the base ball with an error equal to the wavelength of the light used (5000 Å), how will the uncertainty in momentum be compared with the total momentum of the base ball ?
Answer» <html><body><p><br/></p>Solution :`m = 200//1000 = 0.2 kg, v = 30 xx 10^(2) m s^(-1), Delta x = 5000 Å = 5000 xx 10^(-10) m = <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> xx 10^(-7) m` <br/> `Delta x. Delta p = h//4p pi`. Calculate `<a href="https://interviewquestions.tuteehub.com/tag/deltap-2053537" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAP">DELTAP</a>`. <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> `p - <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>`. Calculate `Delta p//p`</body></html>