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A base ball of mass 200g is moving with a velocity of `30 xx 10^(2) m s^(-1)`. If we can locate the base ball with an error equal to the wavelength of the light used `(5000 Å)`, how will the uncertainty in momentum be compared with the total momentum of the base ball ? |
Answer» Correct Answer - `Delta p//p = 1.75 xx 10^(-31)` `m = 200//1000 = 0.2 kg, v = 30 xx 10^(2) m s^(-1), Delta x = 5000 Å = 5000 xx 10^(-10) m = 5 xx 10^(-7) m` `Delta x. Delta p = h//4p pi`. Calculate `Deltap`. Also `p - mv`. Calculate `Delta p//p` |
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