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A battery of e.m.f. 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed? |
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Answer» Given: E = 10 V, r = 3 Ω, I = 0.5 A To find: i. Resistance of resistor (R) ii. Terminal voltage of battery (V) Formula: I = \(\frac{E}{R+r}\) Calculation: From formula, R = \(\frac{E}{I}-r\) ∴ R = \(\frac{10}{0.5}-3\) = 17 Ω ∴ V = IR = 0.5 × 17 = 8.5 volt |
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