A battery of emf `12V` and internal resistance `2 Omega` is connected two a `4 Omega` resistor. Show that the a voltmeter when placed across cell and across the resistor in turn given the same reading

A battery of emf `12V` and internal resistance `2 Omega` is connected

1.	A battery of emf `12V` and internal resistance `2 Omega` is connected two a `4 Omega` resistor. Show that the a voltmeter when placed across cell and across the resistor in turn given the same reading
Answer» Total resistance `=2+4=6Omega` `(a) 1=(E)/(R )=(12)/(6)=2A` `V=E-Ir=12-2xx2=*"Volt"` `"Voltmeter reading"=8V` `"Ammeter reading"=2A` Now when voltmeter is put parallel to `4Omega` resistance, potential drop across `4Omega` resistance is `4xx2=8V`. So, voltmeter will show `8V`. `(b)` Voltmeter is placed parallel and ammeter in series in the circuit because ammeter is a very low resistance device and voltmeter has very high resistance.

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A battery of emf `12V` and internal resistance `2 Omega` is connected two a `4 Omega` resistor. Show that the a voltmeter when placed across cell and across the resistor in turn given the same reading

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