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A battery of emf `2.0 V` and internal resistance `0.10 Omega` is being charged with a current of `5.0 A`. Find the potential difference between the terminals of the battery? |
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Answer» Potential drop across internal resistance `=Ir=0.1xx5=0.5V` Hence potential difference across terminals `=E+Ir=2+0.5=2.5` volt. |
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