A beaker contains a liquid of volume `V_0`. A solid block of volume V floats in the liquid with 90% of its volume submerged in the liquid. The whole system is heated to raise its temperature by `Delta theta`. It is observed that the height of liquid in the beaker does not change and the solid in now floating with its entire volume submerged. Calculate `Delta theta`. It is given that coefficient of volume expansion of the solid and the glass (beaker) are `gamma_(s)` and `gamma_(g)` respectively.

A beaker contains a liquid of volume `V_0`. A solid block of volume V

1.	A beaker contains a liquid of volume `V_0`. A solid block of volume V floats in the liquid with 90% of its volume submerged in the liquid. The whole system is heated to raise its temperature by `Delta theta`. It is observed that the height of liquid in the beaker does not change and the solid in now floating with its entire volume submerged. Calculate `Delta theta`. It is given that coefficient of volume expansion of the solid and the glass (beaker) are `gamma_(s)` and `gamma_(g)` respectively.
Answer» Correct Answer - `Delta theta=(0.1(V_(0)-V))/((0.9V_(0)+V)gamma_(s)-(V_(0)+0.9V)gamma_(g))`

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