A beam of 5 ke V `alpha`-particles and a beam of 5 ke V electrons are absorbed by a target. The two beams deliver equal amounts of energy to the target per second. If `("mass of "alpha-"particle")/("mass of electron")=7.27xx10^(3)`, what is the value of `("pressure on target due to "alpha - "particle")/("pressure on target due to electron")`?A. `1.38xx10^(-4)`B. `1.17xx10^(-2)`C. 1.45D. 85.3

A beam of 5 ke V `alpha`-particles and a beam of 5 ke V electrons are

1.	A beam of 5 ke V `alpha`-particles and a beam of 5 ke V electrons are absorbed by a target. The two beams deliver equal amounts of energy to the target per second. If `("mass of "alpha-"particle")/("mass of electron")=7.27xx10^(3)`, what is the value of `("pressure on target due to "alpha - "particle")/("pressure on target due to electron")`?A. `1.38xx10^(-4)`B. `1.17xx10^(-2)`C. 1.45D. 85.3
Answer» If n particles each with mass m and speed v collide inelastically with the target per sec. then rate of energy transfer `=nxx(1)/(2)mv^(2)=n(K.E.)` Since Rate of momentum transfer `=nxxmv=nxxsqrt(2m(KE))` Since both beam transfer equal energy, `n_(1)(KE)_(1)=n_(2)(KE)_(2)`, but `KE_(1)=KE_(2)rArr n_(1)=n_(2)` `:.` ratio of momentum transferred `=(n_(1)sqrt(2m_(1)(KE)_(1)))/(n_(2)sqrt(2m_(2)(KE)_(2)))=(sqrt(m_(1)))/(sqrt(m_(2)))=sqrt(7270)`

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