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A beam of 5 ke V alpha-particlesand a beam of 5 ke V electronsare absorbed by a target. The two beams deliver equal amountsof energy to the target per second. If ("mass of "alpha-"particle")/("mass of electron")=7.27xx10^(3), what is the value of ("pressure on target due to "alpha - "particle")/("pressure on target due to electron")? |
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Answer» `1.38xx10^(-4)` then rate of energy transfer `=nxx(1)/(2)MV^(2)=n(K.E.)` SINCE Rate of momentum transfer `=nxxmv=nxxsqrt(2m(KE))` Since both beam transfer equal energy, `n_(1)(KE)_(1)=n_(2)(KE)_(2)`, but `KE_(1)=KE_(2)rArr n_(1)=n_(2)` `:.` RATIO of momentum transferred `=(n_(1)sqrt(2m_(1)(KE)_(1)))/(n_(2)sqrt(2m_(2)(KE)_(2)))=(sqrt(m_(1)))/(sqrt(m_(2)))=sqrt(7270)` |
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