1.

A beam of light travelling along x-axis is described by the magnetic field, `E_y=(600 Vm^-1) sin omega (t-x//c)` Calculating the maximum electric and magnetic forces on a charge q=2e, moving along y-axis with a speed of `3xx10^7m//s`, where `e=1.6xx10^(-19)C`.

Answer» Correct Answer - `1.92xx10^-16N; 1.92xx10^(-17)N`
`B_0=(E_0)/c=600/(3xx10^8)=2xx10^-6T`,
which is along Z-axis,
Thus maximum electric force,
`F_e=qE_0=2eE_0=2xx1.6xx10^(-19)xx600`
`1.92xx10^(-16)N`
Maximum magnetic force,
`F_m=qvB_0=2evB_0`
`=2xx1.6xx10^(-19)xx3xx10^7xx2xx10^-6`
`=1.92xx10^(-17)N`


Discussion

No Comment Found

Related InterviewSolutions