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A beam of specific kind of particles of velocity 2.1 xx 10^7 m/s is scattered by a gold (z = 79) nucleli, Find out specific charge (charge/mass) of this particle if the distance of closet approach is 2.5 xx 10^(-14) m.

Answer» <html><body><p>`4.84xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> ` C/kg<br/>`4.84 xx 10^(-7)` C/kg<br/>`2.42 xx 10^(7)` C/kg<br/>`3xx 10^(-12)` C/kg</p>Solution :`1/2 mv^2 = (K(q_1)q_2)/(r) implies (q_2)/(m) = (r.v^2)/(2k.q_1.Z)` <br/>`implies(q_2)/(m) = (2.5 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)xx (2.1 xx 10^7)^2)/(2xx 9xx10^9 xx <a href="https://interviewquestions.tuteehub.com/tag/79-335953" style="font-weight:bold;" target="_blank" title="Click to know more about 79">79</a> xx 1.6 xx 10^(-19))` <br/>`implies4.84 xx 10^7` coulomb/kg</body></html>


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