1.

A beam of specific kind of particles of velocity 2.1 xx 10^7 m/s is scattered by a gold (z = 79) nucleli, Find out specific charge (charge/mass) of this particle if the distance of closet approach is 2.5 xx 10^(-14) m.

Answer»

`4.84xx 10^7 ` C/kg
`4.84 xx 10^(-7)` C/kg
`2.42 xx 10^(7)` C/kg
`3xx 10^(-12)` C/kg

Solution :`1/2 mv^2 = (K(q_1)q_2)/(r) implies (q_2)/(m) = (r.v^2)/(2k.q_1.Z)`
`implies(q_2)/(m) = (2.5 xx 10^(-14)xx (2.1 xx 10^7)^2)/(2xx 9xx10^9 xx 79 xx 1.6 xx 10^(-19))`
`implies4.84 xx 10^7` coulomb/kg


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