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A Bernoulli variate with parameter p = 0.4, then find the probability for x = 1 and write down mean and variance. |
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Answer» Given : p = 0.4, ∴ 1 – p = 1 – 0.4 = 0.6 Then p(x = 1) = (0.4)1 (1 – 0.4)1-1 = 0.4 x 0.60 = 0.4 Mean p = 0.4, variance = p( 1 – p) = 0.4 x 0.6 = 0.24. |
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