A biconvex lens has a focal length 2/3 times the radius of curvature o

1.	A biconvex lens has a focal length 2/3 times the radius of curvature of either surface. Calculate the refractive index of lens material.
Answer» 1/f = (n - 1) (1/R₁ - 1/R₂) For biconvex lens R₁= + R, R₂ = - R Given f = 2/3R ∴ 3/2R = (n -1) (2/R) => (n -1) = 3/4 => n = 1 + 3/4 = 7/4

A biconvex lens has a focal length 2/3 times the radius of curvature of either surface. Calculate the refractive index of lens material.

Answer»

1/f = (n - 1) (1/R₁ - 1/R₂)

For biconvex lens R₁= + R, R₂ = - R

Given f = 2/3R

∴ 3/2R = (n -1) (2/R) => (n -1) = 3/4 => n = 1 + 3/4 = 7/4

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A biconvex lens has a focal length 2/3 times the radius of curvature of either surface. Calculate the refractive index of lens material.

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