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A bike startingh from rest picks up velocity of 72 `km h^(-1)` over distance of 40m. Calculate its accleration |
Answer» Given `u=0` `v=72km h^(-1)=72xx(5)/(18)=20 m s^(-1)` `s=40 m` using `v^(2)-u^(2)=2as` `(20)^(2)-0=2axx40` `a=(400)/(2xx40)=5 m s^(-2)` |
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