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A bin contains 4 red and 6 blue balls and three balls are drawn at random. Find the probability such that both are of the same color.(a) \(\frac{10}{28}\)(b) \(\frac{1}{5}\)(c) \(\frac{1}{10}\)(d) \(\frac{4}{7}\)The question was posed to me by my college professor while I was bunking the class.I'd like to ask this question from Discrete Probability topic in portion Discrete Probability of Discrete Mathematics

Answer»

Right option is (B) \(\frac{1}{5}\)

Best explanation: TOTAL no of balls = 10. Number of ways drawing 3 balls at random out of 10 = ^10C3 = 120. Probability of drawing 3 balls of same colour = ^4C3 + ^6C3 = 24. HENCE, the required probability is \(\frac{24}{120} = \frac{1}{5}\).



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