A bird of 3 kg is flying with a constant velocity of (2hati-4hatj)m//s and another bird of 2 kg with (2hati+6hatj)m//s. Then, the velocity of centre of mass of the system of two bird ……….. Is m/s.

A bird of 3 kg is flying with a constant velocity of (2hati-4hatj)m//s

1.	A bird of 3 kg is flying with a constant velocity of (2hati-4hatj)m//s and another bird of 2 kg with (2hati+6hatj)m//s. Then, the velocity of centre of mass of the system of two bird ……….. Is m/s.
Answer» `10hati+10hatj` `2hati+2hatj` `2hati-2hatj` `2hati+0hatj` Solution :`vecv_(CM)=(m_(1)vec(v_(1))+m_(2)vec(v_(2)))/(m_(1)+m_(2))` `=(3(2hati-4hatj)+2(2hati+6hatj))/(2+3)` `=(6hati-12hatj+4hati+12hatj)/(5)` `=(10hati+0hatj)/(5)` `=2hati+0hatj`