1.

A bird of mass 1.23 kg is able to haver by imparting a downward velocity of `10 m//s` uniformly to air of density `rho kg//m^(3)` over an effective area `0.1m^(2)` the acceleration due to gravity is `10m//s^(2)` then the magnitude of `rho` in `kg//m^(3)`A. `0.34`B. `0.89`C. `1.23`D. `4.8`

Answer» Correct Answer - C
Weight of bird `=` force excted by the bird by moving its wings `rhoAu^(2)=mg (F=Au^(2)rho)`


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