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A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate isA. 168B. 192C. 188D. 182 |
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Answer» Correct Answer - C Given, equivalent mass of bivalent metal, `M^(2+)=32` `:.` Atomic mass of `M=32xx2=64` The metal nitrate formed has the formula `M(NO_(3))_(2)` `:.` Molecular mass of the metal nitrate `=64+28+96=188`. |
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