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A black hole is a body from whose surface nothing ever escape. What is the condition for a uniform spherical mass m to be a black hole? What should be the radius of such a black hole if its mass is the same as that of earth? |
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Answer» From Einstein’s special theory of relativity, we know that the speed of light, c = (3 x 108 ms−1 ) cannot be exceeded by any moving particle. Thus c is the upper limit to the projectile escape speed. i.e., ve = \(\big(\frac{2GM}{R}\big)^{\frac{1}{2}}\leq e\) if M = Me then R = \(\frac{2GMe}{c^2}\) = \(\frac{2\times(6.67\times10^{-11})\times(6\times10^{24)}}{(3\times10^8)^2}\) = 8.9 x 10-3 m = 1 cm It means the earth can act as a black hole. If it shrinks to a very small size of nearby 1 cm radius, which is the size of a berry. |
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