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A blacksmith fixes iron ring on the rim of the wooden wheel of a bullock cart. The diameter of the rim and the ring are 5.243 m and 5.231 m respectivelyat 27^(@)C. To what temperature should the ring be heated so as to fit the rim of the wheel ? Coefficient of linear expansion of iron = 1.20 xx 10^(-5) K^(-1) |
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Answer» SOLUTION :`d_(2)=d_(1)[1+alphaDeltat]` `5.243=5231[1+1.2xx10^(-5)(T-30)]` `[(5243)/(5231)-1]=1.2xx10^(-5)(T-300)` `T=191+300=491k=218^(@)`C |
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