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A blacksmith fixes Iron ring on the rim of the wooden wheel of a horse cart. The diameter of the rim and the fron ring are 5.243 m " and " 5.231m,respectively at 27 ^(@)C. To what temperature should the ring be heated so as to fit the rim of the wheel? |
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Answer» Solution :GIVEN, `T_(1) = 27^(@) C` ` L_(T 1) = 5.231 m` ` L_(T2) = 5.243 m` So, ` L_(T2) = L_(T1) [1 + alpha_(1) (T_(2) - T_(1)]` ` 5.243 m = 5.231 m [1 + 1.20 xx 10^(-5) K^(-1) (T_(2) - 27^(@) C)]` or `T_(2) = 218^(@) C`. |
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