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A blacksmith fixes iron ring on the rim of the wooden wheel of a bullock cart. The diameter of the rim and the iron ring are 5.243 m and 5.231 m respectively at 27°C. To what temperature should the ring be heated so as to fit the rim of the wheel ? |
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Answer» Given, T = 27°C, LT1 = 5.231 m LT2 = 5.243 m So, LT2 = LT1 [1 + α1 (T2 - T1)] ⇒ 5.243 = 5.231 [1 + 1.20 x 10-5°C-1 (T2 - 27°C)] or, T2 = 218°C |
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