A block A of mass m_1 rests on a horizontal table. A light string connected to it passes over a frictionless pully at the edge of the table and from its other end another block B of mass m2 is suspended. The coefficient of kinetic friction between the block and the table is H. When the block A is sliding on the table, the tension in the string is

A block A of mass m_1 rests on a horizontal table. A light string conn

1.	A block A of mass m_1 rests on a horizontal table. A light string connected to it passes over a frictionless pully at the edge of the table and from its other end another block B of mass m2 is suspended. The coefficient of kinetic friction between the block and the table is H. When the block A is sliding on the table, the tension in the string is
Answer» `(m_1 m_2(1+mu _k ) g)/( (m_1 +m_2))` `(m_1m_2 (1- mu_k)g)/((m_1) +m_2)` `((m_2+mu_k m_1)g)/((m_1 +m_2))` `((m_2 -mu_k m_1) g)/((m_1 +m_2))` Solution :Givensituation is shownin thefigure here`,N= m_1 g ,f = mu_k N = mu_k m_1g `…(i) Leta be theacceleationon BLOCKS . equationof MOTIONFOR AAND B ` T-f = m_1 a … (ii) ` `m_2 g - T =m_2 a…(III)` Addingequation(ii) and (iii) we get ` m_2 g- f = (m_1 +m_2) a` ` a =(m_2g-f)/( m_1 +m_2)` substitingvalueof ainequation(iii) ` T = m_2 g -m_2((m_2 g -f))/(m_1 +m_2)` `=(m_1 m_2g + m_1 m_2mu_s g)/(m_1 +m_2) = (m_1 m_2 (1 + mu _s ) g)/( m_1 +m_2)` ( using(i))