A block A, whose weight is 200 N, is pulled up a slope of length 5 m b

1.	A block A, whose weight is 200 N, is pulled up a slope of length 5 m by means of a constant force F (= 150 N) as illustrated in Fig 2.13(a) what is the work done by the force F in moving the block A, 5 m along the slope?(b) By how much has the potential energy of the block A increased?(c) Account for the difference in work done by the force and the increase in potential energy of the block.
Answer» F = 150N (a) Work done by the force in moving the block 5m along the slope = Force x displacement in the direction of force = 150 × 5 =750 J (b) The potential energy gained by the block U = mgh where h = 3m = 200 × 3 = 600 J (c) The difference i.e., 150 J energy is used in doing work against friction between the block and the slope, which will appear as heat energy.

A block A, whose weight is 200 N, is pulled up a slope of length 5 m by means of a constant force F (= 150 N) as illustrated in Fig 2.13(a) what is the work done by the force F in moving the block A, 5 m along the slope?(b) By how much has the potential energy of the block A increased?(c) Account for the difference in work done by the force and the increase in potential energy of the block.

Answer»

F = 150N

(a) Work done by the force in moving the block 5m along the slope = Force x displacement in the direction of force = 150 × 5 =750 J

(b) The potential energy gained by the block

U = mgh where h = 3m

= 200 × 3 = 600 J

(c) The difference i.e., 150 J energy is used in doing work against friction between the block and the slope, which will appear as heat energy.