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A block at rest explodes into 3 parts are -2phatj and phatj. Calculate the magnitude of the momentum of third part. |
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Answer» SOLUTION :Let `vecP` be the momentum of the third particle after the explosion of bomb. ACCORDING to law of conservation of momentum,`-2pvecj+pvecj+vecP``=0(or)vecP=2pveci-pvecj` `P=sqrt(2P)^(2)+(-p)^(2)=psqrt5` |
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