A block is kept on a frictionless inclined surface with angle of inclination alpha. The incline is given an acceleration ‘a’ to keep the block stationary. Then 'a' is equal to

A block is kept on a frictionless inclined surface with angle of incli

1.	A block is kept on a frictionless inclined surface with angle of inclination alpha. The incline is given an acceleration ‘a’ to keep the block stationary. Then 'a' is equal to
Answer» `(G)/(TAN ALPHA)` `g "cosec "alpha` g `g tan alpha` Solution :`ma cos alpha=mg sin alpha`