1.

A block is kept on a rough horizontal plank. The coefficient of friction between the block and the plank is 1//2. The plank is undergoing SHM of angular frequency 10 rad//s. Find the maximum umplitude of plank in which the block does not slip over the plank (g = 10 m//s^(2)).

Answer»

SOLUTION :Maximum acceleration in SHM is `a_("max")= omega^(2)A` this will be provided to the block by friction. HENCE, `a_("max")= mug` or `omega^(2)A=mug`
or `a= (mug)/(omega^(2))= (((1)/(2))(10))/((10)^(2))= 0.05 m= 5CM`


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