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A block is kept on a rough horizontal plank. The coefficient of friction between the block and the plank is 1/2. The plank is unergoing SHM of angular frequency 10 rad/s. Find the maximum amplitude of plank in which the block does not slip over the plank (g=10m//s^(2)) |
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Answer» SOLUTION :MAXIMUM acceleration in SHM is `a_("max")=OMEGA^(2)A` this will be provided to the block by friction. HENCE `a_("max")=mug` or `omega^(2)A=mug` or `a=(mug)/(omega^(2))=((1/2)(10))/((10)^(2))=0.05m=5cm` |
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