A block is moving on an inclined plane making an angle 45^(@) with the horizontal and the coefficient of friction is mu . The force required to just push it up the inclined plane is 3 times the force required to just preventit from sliding down . If we define N = 10 mu , then N is :

A block is moving on an inclined plane making an angle 45^(@) with the

1.	A block is moving on an inclined plane making an angle 45^(@) with the horizontal and the coefficient of friction is mu . The force required to just push it up the inclined plane is 3 times the force required to just preventit from sliding down . If we define N = 10 mu , then N is :
Answer» Solution :`F_(1) = 3F_(2)` mg (SIN `45^(@) + mu` cos `45^(@)`) = 3 mg (sin `45^(@) - mu "cos" 45^(@))` `(1)/(sqrt2) ( 1+ mu) = (3)/(sqrt2) (1 - mu)` `mu = 0.5` `therefore "" N= 10 mu` = `10 XX 0.5` N = 5