A block is moving on an inclined plane making an angle `45^(@)` with the horizontal and the coefficient of friction is `mu` . The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down . If we define `N = 10 mu` , then N is :

A block is moving on an inclined plane making an angle `45^(@)` with t

1.	A block is moving on an inclined plane making an angle `45^(@)` with the horizontal and the coefficient of friction is `mu` . The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down . If we define `N = 10 mu` , then N is :
Answer» Correct Answer - 5 `F_(1) = 3F_(2)` mg (sin `45^(@) + mu` cos `45^(@)`) = 3 mg (sin `45^(@) - mu "cos" 45^(@))` `(1)/(sqrt2) ( 1+ mu) = (3)/(sqrt2) (1 - mu)` `mu = 0.5` `therefore " " N = 10 mu` = `10 xx 0.5` N = 5

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A block is moving on an inclined plane making an angle `45^(@)` with the horizontal and the coefficient of friction is `mu` . The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down . If we define `N = 10 mu` , then N is :

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