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A block is placed on a rough inclined plane which is fixed in an elevator. The angle of inclination is θ = tan–1(μ), where μ is coefficient of friction between block and the inclined plane. The elevator is accelerated vertically upwards with an acceleration a. The acceleration of the block w.r.t. inclined plane will be

Answer» A block is placed on a rough inclined plane which is fixed in an elevator. The angle of inclination is θ = tan–1(μ), where μ is coefficient of friction between block and the inclined plane. The elevator is accelerated vertically upwards with an acceleration a. The acceleration of the block w.r.t. inclined plane will be


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