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A block is sliding along an inclined plane as shown in figure . If the acceleration of chamber is `a` as shown in figure. The time required to cover a distance `L` along inclined is A. `sqrt((2L)/(g sin theta-a cos theta))`B. `sqrt((2L)/(g sin theta+a sin theta))`C. `sqrt((2L)/(g sin theta+a cos theta))`D. `sqrt((2L)/(g sin theta))` |
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Answer» Correct Answer - C `f_("net")(downward) =mg sin theta + ma cos theta` ` =m (g sin theta + a cos theta)` `:.g_(eff) = g sin theta + a cos theta, T = sqrt((2L)/(g_(ef))` . |
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