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A block of `4kg` mass starts at rest and slides a distance `d` down a friction less incline ( angle `30^@`) where it runs into a spring of negligible mass. The block slides an additional `25cm` before it is brought to rest momentarily by compressing the spring. The force constant of the spring is `400Nm^-1`. The value of `d` is (take `g=10ms^-2`) A. 25 cmB. 37.5 cmC. 62.5 cmD. None of the above |
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Answer» Correct Answer - C `h=(1)/(2)g t^(2)=(1)/(2)xx10xx4=20m`. The height of the ball from ground at `t = 2 s " is "45-20=25m` |
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