A block of Ag of mass x kg hanging from a string is immersed in a liquid of relative density 0.72. If the relative density of Ag is 10 and tension in the string is 37.12 N then compute the mass of Ag block.

A block of Ag of mass x kg hanging from a string is immersed in a liqu

1.	A block of Ag of mass x kg hanging from a string is immersed in a liquid of relative density 0.72. If the relative density of Ag is 10 and tension in the string is 37.12 N then compute the mass of Ag block.
Answer» Solution :From the terminal velocity condition, `F_G - U= F "" F = T , m = X` `MG - mg ((rho_w)/(rho)) = T` `mg[1 - (0.72)/10] = 37.12` `9.8x [1 - 0.072] = 37.12` `9.0944 x = 37.12` `x = 4KG`