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A block of mass `1 kg` moving with a speed of `4 ms^(-1)`, collides with another block of mass `2 kg` which is at rest. If the lighter block comes to rest after collision, then the speed of the heavier body isA. `2 ms^(-1)`B. `1 ms^(-1)`C. `1.5 ms^(-1)`D. `0.5 ms^(-1)` |
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Answer» Correct Answer - A `m_(1)u_(1)+m_(2)u_(2) = m_(1)v_(1)+m_(2)v_(2)` |
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