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A block of mass 10 kg is moving in x-direction with a constant speed of 10 ms^(-1). It is subjected to a retarding force F = - 0.1x J m^(-1) during its travel from x = 20 m to x = 30 m. Its final kinetic energy will be |
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Answer» 475 J `:. K_f - 1/2 xx 10 xx 10^(2) = INT F dx or K_f - 500 = int_(20)^(30) - 0.1 x dx` or `K_f - 500 = -0.1 [(x^2)/(2)]_(20)^(30) = - 0.1 [(900 - 400)/(2)] = -25` or `K_f = 500 - 25 = 475 J`. |
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