A block of mass 10 kg is placed on a long trolley. The coefficient of

1.	A block of mass 10 kg is placed on a long trolley. The coefficient of friction between the block and trolley is 0.2. The trolley accelerates from rest with 0.5 m/s2 for 20 s. then what is the friction force?
Answer» Answer: (3) 5N Given; Mass of the block m=10kg Acceleration of the trolley a=0.5m/s² As per newtons second law of motion, the force on the block by the motion of the trolley is given by the relation: F= ma 10×0.5= 5N

A block of mass 10 kg is placed on a long trolley. The coefficient of friction between the block and trolley is 0.2. The trolley accelerates from rest with 0.5 m/s2 for 20 s. then what is the friction force?

Answer»

Answer: (3) 5N

Given;
Mass of the block m=10kg
Acceleration of the trolley a=0.5m/s²

As per newtons second law of motion, the force on the block by the motion of the trolley is given by the relation:
F= ma
10×0.5= 5N