A block of mass 100 g is lying on an inclined plane of angle 30°. The frictional force on thisblock …….N.

A block of mass 100 g is lying on an inclined plane of angle 30°. The

1.	A block of mass 100 g is lying on an inclined plane of angle 30°. The frictional force on thisblock …….N.
Answer» <html><body><p>`4.9xx10^(2)`<br/>`4.9xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`4.9xx10^(-1)`<br/>`4.9 xx10^(1)`</p>Solution :Weight of the blockW=mg<br/> Thecomponentof thisweightparallelto thesurfaceof aslopeW sin `theta` <br/><a href="https://interviewquestions.tuteehub.com/tag/givesthe-2674492" style="font-weight:bold;" target="_blank" title="Click to know more about GIVESTHE">GIVESTHE</a> frictionforce<br/> <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = mgsin `theta` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C05_E06_015_S01.png" width="80%"/><br/>`=mgsin <a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)=0.1 xx 9.8xx (1)/(2) = 0.49 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>` <br/> `f= 4.9 xx 10^(-1) N`</body></html>