A block of mass 10kg is dragged across a horizontal surface by pulling the blockwith force of 100N. The force is applied by attaching a chord to the block. The chord is inclined at an angle of 60^(@) with the horizontal. If the coefficient of kinetic friction is 0.2 what is theacceleration of the block ?

A block of mass 10kg is dragged across a horizontal surface by pulling

1.	A block of mass 10kg is dragged across a horizontal surface by pulling the blockwith force of 100N. The force is applied by attaching a chord to the block. The chord is inclined at an angle of 60^(@) with the horizontal. If the coefficient of kinetic friction is 0.2 what is theacceleration of the block ?
Answer» Solution :`m=10kg`, `F=100N` `THETA=60^(@)`, `mu_(K)=0.2`, `a=?` Horizontal component of the applied force `=F cos theta` `=100xxcos60=50N` FRICTIONAL force opposing the motion of the block `=mu_(k)mg` `=0.2xx10xx9.8=19.6N` NET force acting on the block `=Fcostheta-mu_(k)mg` `=50-19.6=30.4N` ACCELERATION of the block `=("Net force")/("Mass")=(30.4)/(10)=3.04m//s^(2)` `=3.04m//s^(2)`